Data interpretation question and answers -Line graph data interpretation

Question1:Answer the questions based on the line graph given below.

1.In how many of the given years were the exports more than the imports for company A?

• (a)2
• (b)3
• (c)4
• (d)5
• (e)6

2.In which year(s) was the difference between import and export of the company B is maximum?

• (a)2000
• (b)1996
• (c)1998 and 2000
• (d)Cannot be determined
• (e)None of the above

3.If the export of the company A in 1998 were Rs.237 crores, what was the amount of import in that year?

• (a)Rs.189.6 crores
• (b)Rs.243 crores
• (c)Rs.281 crores
• (d)Rs.316 crores
• (e)None of the above

4.If the import of company A in 1997 were increased by 40%,what would be the ratio of export to the increased import?

• (a)1.2
• (b)1.25
• (c)1.30
• (d)none of these
• (e)Cannot be determined

5.In 1995, the export of company A was double that of company B. If the import of company A during the year was Rs.180 crores, what was the approximate imports of the company B during that year?

• (a)Rs.190 crores
• (b)Rs.210 crores
• (c)Rs.225 crores
• (d)Cannot be determined
• (e)None of the above

Solutions:

Sol.1.(b).export is more than import => export to import ratio is greater than 1.From the graph it is clear that for company A, in the years 1995,1996 and 1997 export is more than import.

Sol.2.(d)Only ratio is given. For getting the difference amount of export or import is needed. So ,difference cannot be determined.

Sol.3.(d)Let the amount of A imports of Company A in 1998 be Rs.x crores  Then, (237/x )= 0.75 => x = 316.

Sol.4.(b)In 1997 for Company A we have :E/I= 1.75 => E=1.75I(read E=Export and I=Import)

Now required import I’=I+I *40/100 =1.4I

New ratio E/I’ = 1.75I / 1.4I =1.25

Sol.5.(b)In 1995 for company A,E_A/I_A=1.75………..(i)

For company B, E_B/I_B=0.75…………………………….(ii)

Given E_A=2E_B....................................................(iii)

Substitute I_A=Rs.180 crores in  (i) we get E_A= Rs.315 crores.

Substituting value of E_A  in (iii) we get E_B=Rs. 315/2 crores

I_B= E_B/ 0.75 = Rs.210 crores.

simon     10:24:00     No comments:

Data interpretation question and answers -Pie chart data interpretation

Question1: Study the following pi-chart and answer the questions that follows.

1.What is the ratio of car sales together in the months of March and April to that of total car sales in the month of January.

• a) 14:5
• b) 16:5
• c) 7:3
• d) 7:2
• e) None of these

2.What is the percentage change in the car sale in the month of June with respect to previous month.(appxmt value)

• a) 2% increase
• b) 2% decrease
• c) 4% increase
• d) 4% decrease
• e) 6% decrease

3.Number of car sale in April is what percent higher than number of car sales in March

• a) 45%
• b) 38%
• c) 39%
• d) 40%
• e) 32%

4.Total number of sales together in January and February is what percentage of total sales in six months?

• a) 23%
• b) 23.90%
• c) 23.58%
• d) 24.23%
• e) 26.75%

5.Number of sales in July is 25% higher than number of sales in March and number of sales in August is 10% higher than number of sales in July. Then what is the difference between number of sales in June and August?

• a) 34
• b) 24
• c) 33
• d) 23
• e) 13

Solutions;
Sol.1.(b)
Car sales together in the months of March and April=40+96
Car sales in the month of January=30
Required ratio=96:30=16:5




Sol.2.(e)
Change in the car sale in the month of June with respect to previous month=34-32=2
Required percentage= (2/34)*100=5.88%(6% appxmt)

Sol.3.(d)
Required percentage=[(56-40)/40]*100 %=40%

Sol.4.(c).Required percentage=[(30+20)/212]*100% = 23.58%

Sol.5.(d). Number of sales in July=(125/100) *40 =50
Number of sales in August=(110/100)*50=55
Difference between number of sales in June and August=55-32=23

simon     23:32:00     No comments:

Data interpretation -Bar graph data Interpretation questions

Question1:The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991-92 to 1998-99. Answer the questions based on this graph.

1.The foreign exchange reserves in 1997-93 was how many times that in 1994-95 ?

• (a) 0.7
• (b) 1.2
• (c) 1.4
• (d) 1.5
• (e) 1.8 1

2.What was the percentage increase in the foreign exchange reserves in 1997-98 over

• 1993-94 ?
• (a)100
• (b)150
• (c)200
• (d)620
• (e)2520

3.For which year, the percent increase of foreign exchange reserves over the previous-year,is the highest?

• (a)1992-93
• (b)1993-94
• (c)1994-95
• (d)1996-97
• (e)1997-98

4. The foreign exchange reserves in 1996-97 were approximately what percent of the average foreign exchange reserves over the period under review ? ,

• (a) 95%
• (b) 110%
• (c) 115%
• (d) 125%
• (e) 140%

5, The ratio of the number of years, in which the foreign exchange reserves are above the

average reserves, to those in which the reserves are below the average reserves, is :

• (a)2:6
• (b)3:4
• (c)3:5
• (d)4;4
• (e)5:3

Solutions:

Sol. 1.(d) : Required ratio = 5040/3360=1.5

Sol.2. (a). Foreign exchange reseryes in 1997-98 = 5040 million US $

Foreign exchange reserves in 1993-94 = 2520 million US $

Increase = (5040 — 2520) = 2520 million US $.

Percentage increase =[ (2520/2520) x 100)]% = 100%.

Sol.3. (a) : There is an increase in foreign exchange reserves during the years 1992-93,

1994-95 1996-97 and 1997-98 as compared to previous year (as shown by

bar-graph).

The percentage increase in reserves during these years compared to previous

year are :

(i) For 1992-93 =[{(3720-2640)/2640 }* 100] % = 40.91%

(ii) F01‘ 1994-95 =[{(3360 - 2520)/2520}* 100] % = 33.33%

(iii) For 1996-97 =[{(4320 - 3120)/3120}*100] % = 38.46%

(iv) For 1997-98 =[{ (5040 - 4320)/4320}*100] % = 16.67%

Clearly, the percentage increase over previous year is highest for 1992-93.

Sol.4. (d) : Average foreign exchange reserves over the given period

= [(2640 + 3720 + 2520 + 3360 + 3120+ 4320 + 5040 + 3120)] million US $

= 3480 million US $.

Foreign exchange reserves in 1996-97 = 4320 million US $.

Required Percentage = [( 4320/3480)*100)]% = 124.14% = 125%.

Sol.5. (c)Average foreign exchange reserves over the given period = 3480 million US$.

The country had reserves above 3480 million US $ during the years 1992-93, 1996-97 and 1997-98 ie., for 3 years and below 3480 million US$ during the years 1991-92, 1993-94, 1994-95, 1995-96 and 1998-99 ie., for5 years.

Hence, required ratio = 3 :5

Question2:The Bar graph provided below gives the sales of books from six branches of a publishing company during two consecutive years 2000 and 2001.Answer the questions based on this graph.

1. Total sales of branches B1, B3 and B5 together for both the years (in thousand numbers)is

• (a) 250
• (b) 310
• (c) 435
• (d) 560
• (e) 585

2.Total sales of branch B6 for both the years is what percent of the total sales of branch

B3 for both-the years ?

• (a) 68.54%
• (b) 71.11%
• (c) 73.17%
• (d) 75.55%
• (e) 77.26%

3.What is the average sale of all the branches (in thousand numbers) for the year 2000 ?

• (a)73
• (b) 80
• (c) 83
• (d) 88
• (e) 95 .

4.What  is the ratio of the total sales of’ branch B2 for -both years to the total sales of

branch B4 for both years ?

• (a)2:3 
• (b)3:5
• (c)425
• (d)5:7
• (e)7:9

5.What percent of the average sales of branches Bl, B2 and B3 in 2001 is the average sales of branches B1, B3 and B6 in 2000 ?

• (a) 75%
• (b) 77.5%
• (c) 82.5%
• (d) 85%
• (e) 87.5%

Solutions:

Sol. 1. (d) : Total sales of branches B1, B3 and B5 for both the years (in thousand numbers) = (80 + 105) + (95 + 110) + (75+ 95) = 560.

Sol. 2. (c) : Required Percentage =  [{(70+80)/(95+110)} *100]% = 73.17%.

Sol.3. (b) : Average sales of all the ,six branches (in thousand numbers) for the year 2000 = (1/6)*[80+ 75 +95 + 85+ 75 + 70] = 80.

Sol.4.(e) : Required [(75+65)/(85+95)]=7/9

Sol.5.(e): Average sales (in thousand numbers) of branches B1, B3 and B6 in 2000

=(1/3)*(8O+95+7O)=245/3

Average sales (in thousand numbers) of branches B1, B2 and B3 in 2001

(1/3)*(105+65+110) =280/3

Required Percentage =[(245/3)/(280/3)]*100% = 87.5%

simon     23:15:00     No comments:

Data interpretation -Tabular data Interpretation questions

Question1. The following table gives the sales of batteries manufactured by a company over the years. Study the table and answer the questions that follow

NUMBER OF DIFFERENT TYPES OF BATTERIES SOLD BY A COMPANY OVER THE YEARS (NUMBERS IN THOUSANDS)

1.The total sales of all the seven years is the maximum for which battery ?

• (a) 4AH
• (b) 7AH
• (c) 32AH
• (d) 35AH
• (e) 55AH

2.What is the difference in the number of 35AH batteries sold in 1993 and 1997 ?

• (a) 24000
• (b) 28000
• (c) 35000
• (d) 39000
• (e) 42000

3.The percentage of 4AH batteries sold to the total number of batteries sold was

maximum in the year :

• (a) 1994
• (b) 1995
• (c) 1996
• (d) 1997
• (e) 1998

4.In the case of which battery there was a continuous decrease in sales from 1992 to 1997 ? -

• (a) 4AH
• (b) 7AH
• (c) 32AH
• (d) 35AH
• (e) 55AH

5.What was the approximate percentage increase in the sales of 55AH batteries in 1998

compared to that in 1992 ?

• (a) 28%
• (b) 31%
• (C) 33%
• (d) 34%
• (e) 37%

Solutions:

Sol. 1. (c) : The total sales (in thousands) of all the seven years for various batteries are :

For 4AH= 75 + 90 + 96 + 105+ 90 + 105 + 115 = 676

For 7AH = 144 + 126 + 114 + 90 + 75 + 60 + 85 = 694

For 32AH = 114 + 103 + 75 +‘150 + 135 + 165 + 160 = 901

For 35AH= 102+84+105+90+75+45+100=-601

For 55 AH = 108 + 126 +1135 + 75 + 90 + 120 + 145 = 799.

Clearly, sales. are maximum in case of 32AH batteries.

Sol.2. (d) : Required difference = [(84 - 45) * 1000] = 39000.

Sol.3. (d) : The percentages of sales of 4AH batteries to the total sales in different

years are : -

For 1992 = [(75/543) * 100]% = 13.81%;

For 1993 = [(90/528*100]% =17.05%

For 1994=[(96/525)*100]%=18.29%

For 1995=[(105/510)*100]%=20.59%

For 1996=[(96/465)*100]%=19.35%

For 1997=[(105/495)*100]%=21.21%

For 1998=[(115/605)*100]%=19.01%

Clearly percentage is maximum in the year 1997.

Sol.4.(b)From the table it is clear that the sales of 7AH batteries have been decreasing continuously from 1992 to 1997.

Sol.5.(d) :Required Percentage =[{(145-108)/108}*100]%=34.26%

Question2.The following table gives the percentage of marks obtained by seven students in six different subjects in an examination. Study the table and answer the questions based on it. The numbers in the bracket give the maximum mark in each subject

 1. What was the aggregate of marks obtained by Sajal in all the six subjects ?

• (a) 409
• (b) 419
• (c) 429
• (d) 439
• (e) 449

2. What is the overall percentage of Tarun ? .

• (a) 52.5%
• (b) 55%
• (c) 60%
• (d) 63%
• (e) 64.5%

3. What are the average marks obtained by all the seven students in Physics ? (rounded off to two digits after decimal)

• (a) 77.26  
• (b) 89.14  
• (c) 91.37
• (d) 96.11
• (e) 103.21

4. The number of students who obtained 60% and above marks in all the subjects is :

• (a) 1
• (b) 2
• (c)3
• (d) None
• (e) None of the above

5. In which subject is the overall percentage the best ?

• (a)History
• (b) Maths
• (c) Physics
• (d) Chemistry
• (e) Geography

Solutions:

Sol.1. (e) : Aggregate marks obtained by Sajal

= [(90% of 150) + (60% of 130) + (70% of 120) + (70% of 100) + (90% of 60)+ (70% of 40)] = 135 + 78 + 84 + 70 + 54 + 28 = 449.

Sol.2.(c) : Aggregate marks obtained by Tarun= [(65% of 150)'+ (35% of 130) + (50% of'120) + (77% of 100) + (80% of 60)+ (80% of 40)] = 97.5 + 45.5 + 60 + 77 + 48 + 32 = 360.

Total maximum marks (of all the six subjects) = (150 + 130 + 120 + 100 + 60 + 40) = 600.

Overall percentage of Tarun =  [(360/600)*100]% = 60%

Sol.3.(b) : Average marks obtained in Physics by all the seven students

= (1/7) * [(90% of 120)+ (80% of 120) + (70% of 120) + (80% of 120)+ (85% of 120)+ (65% of 120)+ (50% of 120))=89.14

Sol.4.(b). From the ‘table it is clear that Sajal and Rohit have 60% or more marks in each of the six subjects.

Sol.5.(b). We shall find the overall percentage (for all the seven students) with respect to each subject.

The overall percentage for any subject is equal to the average of percentage obtained by all the seven students since the maximum marks for any subject is the same for all the students. 

Therefore, Overall percentage for :

(i) Maths = [(1/7)*(90 + 100 + 90 + 80 + 80 + 70 + 65)]%= 82.14%.

(ii) Chemistry = [(1/7)* (50 + 80 + 60 + 65 + 65 + 75 + 35)]%= 61.43%.

(iii) Physics = [(1/7)*(90 + 80 + 70 + 80 + 85 + 65 + 50)]%=74.29%.

(iv) Geography =  [(1/7)* (60 +,40+ 70 + 80 + 95 + 85 + 77)]%= 72.43%.

(v) History =[(1/7)*(70 + 80 + 90 + 60 + 50 + 40 + 80)%=67.14%

(vi) Computer Science =(80+70+70+60+90+60+80)]%=72.86

Clearly percentage is highest for maths.

simon     23:02:00     No comments:

Data interpretation for IBPS,SBI PO and Clerk exams

Data interpretation is an important section in bank exams.In IBPS PO and Clerk exams data interpretation section carries 10 marks.In SBI and SBI associate bank Probationary officer and clerical examination data interpretation is a separate section. Many candidates take  this section lightly and doesn't pay required attention to this section.Preparing data interpretation section will help you lot in time management during bank exams.Here we are sharing some data interpretation questions for bank exam preparation.Questions are fully solved with shortest methods.You can also download data interpretation questions for bank po pdf  ebook from the link provided below.To improve your Data interpretation speed solve maximum model questions.By practicing more and more questions, your brain  will eventually adapt to interpret tabular,pie-chart,bar graph and line graph much faster.

Data interpretation practice questions for bank exams

Data interpretation questions for bank PO and clerk can be categorised into 5 types.Tabular data based data interpretation questions,Pie-chart based data interpretation questions,Line graph data interpretation,Bar graph data interpretation and mixed type data interpretation(Any two of table,line graph,pie-chart,bar graph).Under each section we have provide 2 set of data interpretation questions(5+5 questions each).This Data interpretation questions for ibps po and clerk is fully solved using easiest methods.You can also download this data interpretation questions pdf with solution from the link provided at the end of this page.These fully practice questions on data interpretation is also useful for exams like SBI PO,SBI clerK,RBI assistant,CAT,MAT and other major competitive examinations.

Data interpretation practice set for bank PO and Clerk

• Tabular Data interpretation questions
• Bar Graph Data Interpretation
• Pie-Chart Data Interpretation Questions
• Line Graph Data Interpretation Questions

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simon     22:39:00     No comments: